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Code d'Examen: 1Z0-450
Nom d'Examen: Oracle (Oracle Application Express 3.2: Developing Web Applications)
Questions et réponses: 49 Q&As
Code d'Examen: 1Z1-591
Nom d'Examen: Oracle (Oracle Business Intelligence Foundation Suite 11g Essentials)
Questions et réponses: 118 Q&As
Code d'Examen: 1Z0-047
Nom d'Examen: Oracle (Oracle Database SQL Expert)
Questions et réponses: 260 Q&As
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1Z0-047 Démo gratuit à télécharger: http://www.pass4test.fr/1Z0-047.html
NO.1 View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables. You need to create a
view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order. Which
CREATE VIEW statement would create the view successfully?
A.CREATE OR REPLACE VIEW ord_vu (order_id,order_date) AS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
B.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date;
C.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date;
D.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)||'
NO OF ITEMS' FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date WITH CHECK OPTION;
Answer:B
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NO.2 Which two statements are true regarding the execution of the correlated subqueries? (Choose two.)
A.The nested query executes after the outer query returns the row.
B.The nested query executes first and then the outer query executes.
C.The outer query executes only once for the result returned by the inner query.
D.Each row returned by the outer query is evaluated for the results returned by the inner query.
Answer:A D
Oracle examen certification 1Z0-047 1Z0-047
NO.3 View the Exhibit and examine the structure of the EMPLOYEES table. You want to retrieve hierarchical
data of the employees using the top-down hierarchy. Which SQL clause would let you choose the
direction to walk through the hierarchy tree?
A.WHERE
B.HAVING
C.GROUP BY
D.START WITH
E.CONNECT BY PRIOR
Answer:E
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NO.4 OE and SCOTT are the users in the database. The ORDERS table is owned by OE. Evaluate the
statements issued by the DBA in the following sequence: CREATE ROLE r1; GRANT SELECT, INSERT
ON oe.orders TO r1; GRANT r1 TO scott; GRANT SELECT ON oe.orders TO scott; REVOKE SELECT
ON oe.orders FROM scott; What would be the outcome after executing the statements?
A.SCOTT would be able to query the OE.ORDERS table.
B.SCOTT would not be able to query the OE.ORDERS table.
C.The REVOKE statement would remove the SELECT privilege from SCOTT as well as from the role R1.
D.The REVOKE statement would give an error because the SELECT privilege has been granted to the
role R1.
Answer:A
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NO.5 EMPDET is an external table containing the columns EMPNO and ENAME. Which command would
work in relation to the EMPDET table?
A.UPDATE empdet SET ename = 'Amit' WHERE empno = 1234;
B.DELETE FROM empdet WHERE ename LIKE 'J%';
C.CREATE VIEW empvu AS SELECT * FROM empdept;
D.CREATE INDEX empdet_idx ON empdet(empno);
Answer:C
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NO.6 View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables. You executed the following
query to display PRODUCT_NAME and the number of times the product has been ordered: SELECT
p.product_name, i.item_cnt FROM (SELECT product_id, COUNT (*) item_cnt FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p ON i.product_id = p.product_id; What would
happen when the above statement is executed?
A.The statement would execute successfully to produce the required output.
B.The statement would not execute because inline views and outer joins cannot be used together.
C.The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.
D.The statement would not execute because the GROUP BY clause cannot be used in the inline view.
Answer:A
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NO.7 View the Exhibit and examine the descriptions of ORDER_ITEMS and ORDERS tables. You want to
display the CUSTOMER_ID, PRODUCT_ID, and total (UNIT_PRICE multiplied by QUANTITY) for the
order placed. You also want to display the subtotals for a CUSTOMER_ID as well as for a PRODUCT_ID
for the last six months. Which SQL statement would you execute to get the desired output?
A.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
B.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) HAVING
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
C.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id, oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) >= 6;
D.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id WHERE MONTHS_BETWEEN(order_date, SYSDATE) <= 6
GROUP BY ROLLUP (o.customer_id, oi.product_id) ;
Answer:D
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NO.8 You need to load information about new customers from the NEW_CUST table into the tables CUST
and CUST_SPECIAL. If a new customer has a credit limit greater than 10,000, then the details have to be
inserted into CUST_SPECIAL. All new customer details have to be inserted into the CUST table. Which
technique should be used to load the data most efficiently?
A.external table
B.the MERGE command
C.the multitable INSERT command
D.INSERT using WITH CHECK OPTION
Answer:C
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